MCQ
Co-ordinate of image with respect to origin $c$ will be :-


- A$(-5, 5 \sqrt 3 )$
- B$(5, -5 \sqrt 3 )$
- ✓$( 5 \sqrt 3 , -5)$
- DNone of these

$\therefore $ $x$ -coordinate $=+10 \cos 30^{\circ}=5 \sqrt{3}$
$y$ -coordinate $=-10 \sin 30^{\circ}=-5$
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