MCQ
Co-ordinate of image with respect to origin $c$ will be :-
  • A
    $(-5, 5 \sqrt 3 )$
  • B
    $(5, -5 \sqrt 3 )$
  • $( 5 \sqrt 3 , -5)$
  • D
    None of these

Answer

Correct option: C.
$( 5 \sqrt 3 , -5)$
c
$\Delta \mathrm{AOB} \cong \Delta \mathrm{AIB} \Rightarrow \mathrm{OA}=\mathrm{AI}=10 \mathrm{\,cm}$

$\therefore $ $x$ -coordinate $=+10 \cos 30^{\circ}=5 \sqrt{3}$

$y$ -coordinate $=-10 \sin 30^{\circ}=-5$

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