- A$\frac{9}{16\pi }$
- B$\frac{25}{9\pi }$
- C$\frac{5}{3\pi }$
- ✓$\frac{16}{9\pi }$
$\frac{{dV}}{{dt}} = \pi \left[ {{r^2}\frac{{dh}}{{dt}} + h\,\cdot\,2r\frac{{dr}}{{dt}}} \right]$(r = constant, $\frac{{dr}}{{dt}} = 0$)
hence,$100 = \pi r^2\frac{{dh}}{{dt}}$
$100 = \pi · \frac{{225}}{4} · \frac{{dh}}{{dt}}$(r = $\frac{{15}}{{2}} cm$)
$\frac{{dh}}{{dt}} = \frac{{400}}{{225\pi }} = \frac{{16}}{{9\pi }} cm/min$
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$STATEMENT -1$ : $\mathrm{P}\left(\mathrm{H}_{\mathrm{i}} \mid \mathrm{E}\right)>\mathrm{P}\left(\mathrm{E} \mid \mathrm{H}_{\mathrm{i}}\right) \cdot \mathrm{P}\left(\mathrm{H}_{\mathrm{i}}\right)$ for $\mathrm{i}=1,2, \ldots, \mathrm{n}$ because
$STATEMENT$ $-2: \sum_{1=1}^{\mathrm{n}} \mathrm{P}\left(\mathrm{H}_{\mathrm{i}}\right)=1$