MCQ
Collision diameter is least in case of:
- A$H_2$
- B$He$
- ✓$CO_2$
- D$N_2$
✓
Answer
Correct option: C.
$CO_2$
Collision diameter will be least for the low molecular weight.
$\text{d}\alpha\frac{1}{\text{M}}$
In this case, $Co_2$ has the highest molecular weight.
$\text{d}\alpha\frac{1}{\text{M}}$
In this case, $Co_2$ has the highest molecular weight.
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