MCQ
Coloration of $B{r_2}/CC{l_4}$ will be discharged by
  • Cinnamic acid
  • B
    Benzoic acid
  • C
    $o-$ phthalic acid
  • D
    Acetophenone

Answer

Correct option: A.
Cinnamic acid
a
Cinnamic acid reacts with bromine in carbon tetrachloride to give dibromocinnamic acid.

${{C}_{6}}{{H}_{5}}CH=CHCOOH+B{{r}_{2}}$ $\xrightarrow{CC{{l}_{4}}}$   $\underset{\text{dibromo}\,\,\,\text{cinnamic acid}}{\mathop{\begin{matrix}
   \,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,  \\
   {{C}_{6}}{{H}_{5}}CH-CHCOOH  \\
\end{matrix}}}\,$

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