MCQ
Comment on stereochemistry of products


- ✓diastereomers
- Bracemic
- Csingle stereoisomer
- Dmeso

Two chiral carbons in the product. Configuration of one carbon is fixed. Attack on the carbonyl carbon can be from two sides. Hence products obtained will be diastereomers.
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$I$ . $Zn +$ conc. $HNO_3$ (hot) $\to Zn(NO_3)_2 + X + H_2O$
$II$. $Zn +$ dil. $HNO_3$ (cold) $\to Zn(NO_3)_2 + Y + H_2O$
Compounds $X$ and $Y$ are respectively
