MCQ
Common alum is
- ✓${K_2}S{O_4}.A{l_2}{(S{O_4})_3}.24{H_2}O$
- B${K_2}S{O_4}.C{r_2}{(S{O_4})_3}.24{H_2}O$
- C${K_2}S{O_4}.F{e_2}{(S{O_4})_3}.24{H_2}O$
- D${(N{H_4})_2}S{O_4}.FeS{O_4}.6{H_2}O$
✓
Answer
Correct option: A.
${K_2}S{O_4}.A{l_2}{(S{O_4})_3}.24{H_2}O$
a
Potassium alum is the common alum of commerce whose chemical formula is
Potassium alum is the common alum of commerce whose chemical formula is
$K _2 SO _4 \cdot Al _2\left( SO _4\right)_3 \cdot 24 H _2 O$
Ammonium alum is $\left( NH _4\right) SO _4 \cdot Al _2\left( SO _4\right)_3 \cdot 24 H _2 O$.
Chrome alum is $K _2 SO _4 \cdot Cr _2\left( SO _4\right)_3 \cdot 24 H _2 O$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The correct sequence of reagents used in the preparation of $4 -$bromo$-2-$nitroethyl benzene from benzene is :
→The free energy for a reaction having $\Delta H = 31400\,cal;$. $\Delta S = 32\,cal\,{K^{ - 1}}\,mo{l^{ - 1}}$ at ${1000\,^o}C$ is .......$cal$
→Dehydrohalogenation of an alkyl halide is
$CH \equiv CH\mathop {\xrightarrow{{Ni{{(CN)}_2}}}X}\limits_{{\text{Pressure}}} $ Here $X$ in the reaction
→In the electrochemical cell :
→$Zn \,|\,ZnSO_4\,(0.01\,M)\,||\,CuSO_4\,(1.0\, M)\,|\,Cu,$
the $emf$ of this Daniell cell is $E_1.$ When the concentration of $ZnSO_4$ is changed to $1.0\, M$ and that of $CuSO_4$ changed to $0.01\, M,$ the $emf$ changes to $E_2.$ Fromthe followings, which one is the relationship between $E_1$ and $E_2$ ? (Given, $RT/F = 0.059$)
On passing ${H_2}S$ gas through a solution of $C{u^ + }$ and $Z{n^{ + 2}}$ ions, $CuS $ is precipitated first because
→The correct order in which the $O -O$ bond length increases in the following is
→The type of hybrid orbitals used by chlorine atom in $ClO_2^ - $ is
→Product $(B)$ in the above reaction is
→Zinc forms two important alloys, $(i)$ Brass and $ (ii) $ German silver. Metals present in them mainly are
→