MCQ
Common factor of $17abc, 34ab^2, 51a^2b$ is:
  • A
    $17abc$
  • $17ab$
  • C
    $17ac$
  • D
    $17a^2b^2c$

Answer

Correct option: B.
$17ab$
B.  $17ab$
Solution:
Given, $17 a b c=17 \times a \times b \times c$
$34 a b^2=2 \times 17 \times a \times b \times b $
$34 a^2 b=3 \times 17 \times a \times a \times b$
Now, collecting the common factors, we get $17 \times a \times b=17 a b$

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