Question
Compare the fractions given below: $\frac{4}{9},\frac{5}{6}$
✓
Answer
$L.C.M.$ of $9$ and $6 = (3 \times 3 \times 2) = 18$
Now, we convert $\frac{4}{9}$ and $\frac{5}{6}$ into equivalent fractions having $18$ as the denominator.
$\therefore\frac{4}{9}=\frac{4\times2}{9\times2}=\frac{8}{18}$ and
$\frac{5}{6}=\frac{5\times3}{6\times3}=\frac{15}{18}$
Clearly, $\frac{8}{18}<\frac{15}{18}$
$\therefore\frac{4}{9}<\frac{5}{6}$
Now, we convert $\frac{4}{9}$ and $\frac{5}{6}$ into equivalent fractions having $18$ as the denominator.
$\therefore\frac{4}{9}=\frac{4\times2}{9\times2}=\frac{8}{18}$ and
$\frac{5}{6}=\frac{5\times3}{6\times3}=\frac{15}{18}$
Clearly, $\frac{8}{18}<\frac{15}{18}$
$\therefore\frac{4}{9}<\frac{5}{6}$
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