Question
Compare the fractions given below: $\frac{7}{8},\frac{9}{10}$
✓
Answer
$L.C.M$. of $8$ and $10 = (2 \times 5 \times 2 \times 2) = 40$
Now, we convert $\frac{7}{8}$ and $\frac{9}{10}$
into equivalent fractions having $40$ as the denominator.
$\therefore\frac{7}{8}=\frac{7\times5}{8\times5}=\frac{35}{40}$ and
$\frac{9}{10}=\frac{9\times4}{10\times4}=\frac{36}{40}$
Clearly, $\frac{35}{40}<\frac{36}{40}$
$\therefore\frac{7}{8}<\frac{9}{10}$
Now, we convert $\frac{7}{8}$ and $\frac{9}{10}$
into equivalent fractions having $40$ as the denominator.
$\therefore\frac{7}{8}=\frac{7\times5}{8\times5}=\frac{35}{40}$ and
$\frac{9}{10}=\frac{9\times4}{10\times4}=\frac{36}{40}$
Clearly, $\frac{35}{40}<\frac{36}{40}$
$\therefore\frac{7}{8}<\frac{9}{10}$
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