MCQ
Complementary angle of $72\frac{1^\circ}{2}$ is:
- A$17^\circ$
- B$18\frac{1^\circ}{2}$
- C$21\frac{1^\circ}{2}$
- ✓$17\frac{1^\circ}{2}$
Given angle is $72.5$ or $72\frac{1^\circ}{2}$
Let the other angle $= x$ Sum of complementary angles
$=90^\circ\Rightarrow\text{x}+72\frac{1^\circ}{2}=90^\circ$
$\Rightarrow\text{x}=17\frac{1^\circ}{2}$
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