MCQ
Complete the equation for the following fission process $92^{\mathrm{U}^{235}}+0^{\mathrm{n}^1} \rightarrow 38^{ \mathrm{Sr}^{90}}+\ldots$
  • $54^{\mathrm{Xe}^{148}}+30^{\mathrm{n}^1}$
  • B
    $54^{\mathrm{Xe}^{145}}$
  • C
    $57^{\mathrm {Xe}^{142}}$
  • D
    $54^{\mathrm{Xe}^{142}}+0^{\mathrm{n}^1}$

Answer

Correct option: A.
$54^{\mathrm{Xe}^{148}}+30^{\mathrm{n}^1}$
(a) $54^{\mathrm{Xe}^{148}}+30^{\mathrm{n}^1}$

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