Question
Complete the following activity to solve the given quadratic equation by formula method.$2 x^2+13 x+15=0$
$\text { Activity: } 2 x^2+13 x+15=0$
$a=(\ldots \ldots), b=13, c=15$
$b^2-4 a c=(13)^2-4 \times 2 \times(\ldots \ldots)$
$=169-120$
$b^2-4 a c=49$
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
$x=\frac{-(\ldots \ldots) \pm \sqrt{49}}{4}$
$x=\frac{-13 \pm(\ldots)}{4}$
$x=\frac{6}{4} \quad \text { or } \quad x=\frac{-20}{4}$
X = (….) or x = (….)
$\text { Activity: } 2 x^2+13 x+15=0$
$a=(\ldots \ldots), b=13, c=15$
$b^2-4 a c=(13)^2-4 \times 2 \times(\ldots \ldots)$
$=169-120$
$b^2-4 a c=49$
$x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
$x=\frac{-(\ldots \ldots) \pm \sqrt{49}}{4}$
$x=\frac{-13 \pm(\ldots)}{4}$
$x=\frac{6}{4} \quad \text { or } \quad x=\frac{-20}{4}$
X = (….) or x = (….)