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Model Paper 5 — Economics STD 11 Commerce — Question

CBSE BoardEnglish MediumSTD 11 CommerceEconomicsModel Paper 56 Marks
Question
Complete the following data.
Units of LabourAverage Product (A) (units)Marginal Product (Units)
18-
210-
3-10
49-
5-4
67-
✓

Answer

Labour (Q) (units)Total product (TP) (units)Average product (AP) (Units)Marginal product (MP) (units)
1888
2201012
3301010
43696
54084
64272
For completing this table, we include one more column, Total Product (TP).
For the $1^{\text {st }}$ unit of labour, AP is given as 8 , so, $TP = AP \times$ no. of units $=8 \times 1=8$. For the $1^{\text {st }}$ unit of labour, MP will also be 8 .
For the $2^{\text {nd }}$ unit of labour, AP is given as 10 , so $TP = AP \times$ no. of units $=10 \times 2=20$. $MP = TR$ of $2^{\text {nd }}$ unit - TR of $1^{\text {st }}$ unit $=20-8=12$.
For the $3^{\text {rd }}$ unit of labour, MP is given as 10 , so $TP = TP$ of $2^{\text {nd }}$ unit $+10=20+10=30$. AP $= TP / No$. of units $=30 / 3=10$.
For the $4^{\text {th }}$ unit of labour, AP is given as 9 , so TP $= AP \times$ No. of units $=9 \times 4=36 . MP =$ TP of $4^{\text {th }}$ unit - TP of 3 rd unit $=36-30=6$.
For the $5^{\text {th }}$ unit of labour, MP is given as 4 , so TP will be TP of $4^{\text {th }}$ unit $+4=36+4=40$. $AP = TP / No$. of units $=40 / 5=8$.
For the $6^{\text {th }}$ unit of labour, AP is given as 7 , so TP $= AP \times$ No. of units $=7 \times 6=42 . MP =$ TP of $6^{\text {th }}$ unit - TP of $5^{\text {th }}$ unit $=42-40=2$.

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