Question
Complete the following.

Answer

$\text { Length of rectangle } \Rightarrow 2 x + y +8=4 x - y $
$\Rightarrow x -4 x + y + y =-8$
$\Rightarrow-2 x +2 y =-8$
$\Rightarrow- x + y =-4 \ldots . .(1)$
Breadth of the rectangle $=2 y = x +4$
$\Rightarrow-x+2 y=4 \ldots \ldots .(I I)$
Equating Eq. I and II and change sign of Eq. II
$-x +y = -4$
$x-2y=-4$
$-------$
  $-y=-8$
Substituting $y=8$ in Eq.I
$-x+8=-4$
$-x=-4-8$
$-x=-12$
$x=12$
$\text { Length }=2 \times 12+8+8=40 $
$\text { Breadth }=2 \times 8=16$

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