Question
Complete the table of products.
$\frac{\text { First monomial } \rightarrow}{\text { Second monomial } \downarrow}$ $2x$ $-5y$ $3x^2$ $-4xy$ $7x^2y$ $-9x^2y^2$
$2x$ $4x^2$ - - - - -
$-5y$ - - $-15x^2y$ - - -
$3x^2$ - - - - - -
$-4xy$ - - - - - -
$7x^2y$ - - - - - -
$-9x^2y^2$ - - - - - -

Answer

After doing the product, we get
$\frac{\text { First monomial } \rightarrow}{\text { Second monomial } \downarrow}$ $2x$ $-5y$ $3x^2$ $-4xy$ $7x^2y$ $-9x^2y^2$
$2x$ $4x^2$ $-10xy$ $6x^3$ $-8x^2y$ $14x^3y$ $-18x^3y^2$
$-5y$ $-10xy$ $25y^2$ $-15x^2y$ $20xy^2$ $-35x^2y^2$ $45x^2y^3$
$3x^2$ $6x^3$ $-15x^2y$ $9x^4$ $-12x^3y$ $21x^4y$ $-27x^4y^2$
$-4xy$ $-8x^2y$ $20xy^2$ $-12x^3y$ $16x^2y^2$ $-28x^3y^2$ $36x^3y^3$
$7x^2y$ $14x^3y$ $-35x^2y^2$ $21x^4y$ $-28x^3y^2$ $49x^4y^2$ $-63x^4y^3$
$-9x^2y^2$ $-18x^3y^2$ $45x^2y^3$ $-27x^4y^2$ $36x^3y^3$ $-63x^4y^3$ $81x^4y^4$

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