- A$BaCl_2$
- B$AgNO_3$
- C$PbCl_2$
- ✓All of these
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$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,C{H_2} - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{\,\,CH - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_2} - O - C{H_3}}
\end{array}\xrightarrow{{HI(excess)}}$
$2NO(g) + Cl_2(g) \to 2NOCl(g)$ at $298\, K$
$[Cl_2]$ $[NO]$ Rate $(mol\, L^{-1} \sec^{-1})$
$I$ $0.05\, M$ $0.05\,M$ $1 \times 10^{-3}$
$II$ $0.15\, M$ $0.05\,M$ $3 \times 10^{-3}$
$III$ $0.05\, M$ $0.15\,M$ $9 \times 10^{-3}$
The rate law for the reaction is