MCQ
Complex ion is shown by
- A$Ag$
- B$Au$
- C$Cu$
- ✓All of these
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$(A)$ $AgCN / KCN$
$(B)$ $RCOOAg / RCOOK$
$(C)$ $AgNO _{2} / KNO _{2}$
$(D)$ $AgI / KI$
(Round off to the Nearest Integer) [Given : $R =8.314 \,J mol ^{-1} K ^{-1}$. Assume,
hydrogen is an ideal gas] [Atomic mass off $Fe$ is $55.85\, u$ ]
Reason : The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to ‘inert pair effect’.