MCQ
Complex number $z=\frac{i-1}{\cos (\pi / 3)+i \sin (\pi / 3)}$ polar form is
  • $\sqrt{2}\left(\cos \frac{5 \pi}{12}+ i \sin \frac{5 \pi}{12}\right)$
  • B
    $\sqrt{2}\left(\cos \frac{\pi}{4}+i \sin \frac{\pi}{4}\right)$
  • C
    $\sqrt{2}\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)$
  • D
    None of these

Answer

Correct option: A.
$\sqrt{2}\left(\cos \frac{5 \pi}{12}+ i \sin \frac{5 \pi}{12}\right)$
(A)
$Z=\frac{i-1}{\cos (\pi / 3)+i \sin (\pi / 3)}$
$=\frac{i-1}{\frac{1}{2}+\frac{i \sqrt{3}}{2}}=\frac{2(i-1)}{1+i \sqrt{3}}$
$=\frac{2( i -1)}{1+ i \sqrt{3}} \times \frac{1- i \sqrt{3}}{1- i \sqrt{3}}=\frac{2 i +2 \sqrt{3}-2+2 i \sqrt{3}}{1+3}$
$=\frac{2(-1+i+\sqrt{3}+i \sqrt{3})}{4}$
$=\frac{1}{2}[(\sqrt{3}-1)+ i (\sqrt{3}+1)]$
$\therefore|z|=\sqrt{\frac{1}{4}(3+1-2 \sqrt{3}+3+1+2 \sqrt{3})}=\sqrt{\frac{8}{4}}=\sqrt{2}$
$\theta=\tan ^{-1}\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right)=\tan ^{-1}\left(\frac{1+\frac{1}{\sqrt{3}}}{1-\frac{1}{\sqrt{3}}}\right)$
$=\tan ^{-1} 1+\tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)=\frac{\pi}{4}+\frac{\pi}{6}=\frac{5 \pi}{12}$
∴ the polar form of $z=\sqrt{2}\left(\cos \frac{5 \pi}{12}+i \sin \frac{5 \pi}{12}\right)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free