MCQ
Compound $(A)$ is


- A

- ✓

- C

- D







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$(A)$ $\mathrm{NH}_4 \mathrm{NO}_3$ $(B)$ $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ $(C)$ $\mathrm{Ba}\left(\mathrm{N}_3\right)_2$ $(D)$ $\mathrm{Mg}_3 \mathrm{~N}_2$
Reason : The presence of additional $d-$ electron offer poor screening effect for the outer electrons from increased nuclear charge.
$MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$
Here $10\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to