MCQ
Compound $A$ (molecular formula $C_3 H_8O$) is treated with acidified  potassium dichromate to form a product $B$ (molecular formula $C_3H_6O$). $B$ forms a shining silver mirror on warming with ammonical silver nitrate, $B$ when treated with an aqueous solution of $NH_2NHCONH_2$ and sodium  acetate gives a product $C$. Identify the structure of $C$.
  • $CH_3CH_2CH =NNHCONH_2$
  • B
    $\begin{matrix}
       C{{H}_{3}}C=NHHCON{{H}_{2}}  \\
       |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
       C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
    \end{matrix}$
  • C
    $\begin{matrix}
       C{{H}_{3}}C=NCONHN{{H}_{2}}  \\
       |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
       C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
    \end{matrix}$
  • D
    $CH_3CH_2 CH = NCONHNH_2$

Answer

Correct option: A.
$CH_3CH_2CH =NNHCONH_2$
a
$(A)\, CH_3 - CH_2 - CH_2 - OH$

$(B)\,CH_3 - CH_2-CHO$

give positive Tollen's test. 

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