MCQ
Compound $(A)$ will be

$\mathop {(A)}\limits_{{C_{11}}{H_8}O}  \to $ does not under go self aldol condensation

$\mathop {(A)}\limits_{{C_{11}}{H_8}O} \xrightarrow{{{O_3}}}ph\, - \,CHO\, + \,2B\,\xrightarrow{{A{g^ + }}}$ Oxalic acid

  • A
    $Ph - C \equiv C - C \equiv C - CHO$
  • B
    $Ph - C \equiv C - CH = CH - CHO$
  • $Ph -CH =CH-C \equiv C-CHO$
  • D
    $Ph - CH = CH - C = CH - CO_2H$

Answer

Correct option: C.
$Ph -CH =CH-C \equiv C-CHO$
c
$Ph -CH =CH-C \equiv C-CHO$  $\to $ does not under go self aldol condensation

$Ph -CH =CH-C \equiv C-CHO$ $\xrightarrow{{{O_3}}}ph\, - \,CHO\, + \,2B\,\xrightarrow{{A{g^ + }}}$ Oxalic acid

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