MCQ
Compound $(P)$ is
- ✓
- B
- C
- D
✓
Answer
Correct option: A.
a
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
${H_2}O$ is dipolar, whereas $Be{F_2}$ is not. It is because
→From the ground state electronic configuration of the elements given below, pick up the one with highest value of second ionisation energy.
A button cell used in watches function as following.
→$Zn_{(s)} + Ag_2O_{(s)} + H_2O_{(l)} \rightleftharpoons $$2Ag_{(s)} + Zn^{2+}_{(aq)}+ 2OH^-_{(aq)}$
If half cell potentials are
$Zn^{2+}_{(aq)} + 2e^- \rightarrow Zn_{(s)}\,;\,\, E^o = - 0.76\, V$
$Ag_2O_{(s)} + H_2O_{(l)} + 2e^- \rightarrow 2Ag_{(s)} + 2OH^-_{(aq)}\,,$$E^o = 0.34\, V$
The cell potential will be ........... $V.$
The $pH$ of a ${10^{ - 9}}\,M$ solution of $HCl$ in water is
→The cell reaction of the galvanic cell $C{u_{(s)}}|C{u^{2 + }}_{(aq)}||H{g^{2 + }}_{(aq)}|H{g_{(l)}}$ is
→The products $P$ and $Q$ in the following sequence of reactions, are
→Beilstein test is used for
For the reaction $FeCO_{3(s)} \to FeO_{(s)} + CO_{2(g)}$ $\Delta H = 82.8\,kJ$ at $25\,^oC$. What is $\Delta U$ at $25\,^oC$ ? .....$kJ$
→Concentrated $H_2SO_4$ is not used to prepare $HBr$ from $KBr$ because it
→Which one given below is a non-reducing sugar ?