- A$[Pd(H_2O)_6]Cl_4$
- B$[Pd(H_2O)_4Cl_2]Cl_2.2H_2O$
- ✓$[Pd(H_2O)_3Cl_3]Cl.3H_2O$
- D$[Pd(H_2O)_2Cl_4].4H_2O$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.
$(p)$ $\begin{matrix}
Ph\,\,\,\,\,O\, \\
|\,\,\,\,\,\,\,\,||\,\, \\
Ph-C-C-C{{H}_{3}} \\
|\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \\
\end{matrix}$ $(q)$ $\begin{matrix}
\,Ph\,\,\,\,\,O\, \\
\,\,|\,\,\,\,\,\,\,\,|| \\
Ph-C-C-Et \\
|\,\,\,\,\,\,\,\,\,\, \\
Et\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$
$(r)$ $\begin{matrix}
\,Ph\,\,\,\,\,O\, \\
|\,\,\,\,\,\,\,\,\,\,||\, \\
Ph-C-C-C{{H}_{3}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
Et\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $(s)$ $\begin{matrix}
\,\,\,Ph\,\,\,\,\,O\, \\
\,\,|\,\,\,\,\,\,\,\,|| \\
Ph-C-C-Et \\
|\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\, \\
\end{matrix}$
When $(A)$ and $(B)$ reacts with $H_2SO_4$ products obtained are
( $U$ : आंतरिक ऊर्जा (internal energy), $S$ : एंट्रॉपी (entropy), $p$ : दाब (pressure), $V$ : आयतन (volume), $R$ : गैस नियतांक (gas constant)
(दिया गयाः स्थिर आयतन पर गैस की मोलर ऊष्माधारिता (molar heat capacity at constant volume), $C_{V, m }$ का मान $\frac{5}{2} R$ है)