MCQ
Compound $PdCl_4.6H_2O$ is a hydrated complex; $1$ molal aqueous solution of it has freezing point $269.28\ K$ . Assuming $100\%$ ionization of complex, calculate the molecular formula of the complex ($K_f$ for water $ = 1.86\ K\ kg\,mol^{-1}$)
- A$\left[ {Pd{{\left( {{H_2}O} \right)}_6}} \right]C{l_4}$
- ✓$\left[ {Pd{{\left( {{H_2}O} \right)}_4}C{l_2}} \right]C{l_2}.2{H_2}O$
- C$\left[ {Pd{{\left( {{H_2}O} \right)}_3}C{l_3}} \right]Cl.3{H_2}O$
- D$\left[ {Pd{{\left( {{H_2}O} \right)}_2}C{l_4}} \right]4{H_2}O$
