MCQ
Compound which gives acetone on ozonolysis
- A$C{H_3} - CH = CH - C{H_3}$
- ✓${(C{H_3})_2}C = C{(C{H_3})_2}$
- C${C_6}{H_5}CH = C{H_2}$
- D$C{H_3}CH = C{H_2}$
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$A$. All group $16$ elements form oxides of general formula $\mathrm{EO}_2$ and $\mathrm{EO}_3$ where $\mathrm{E}=\mathrm{S}, \mathrm{Se}, \mathrm{Te}$ and Po. Both the types of oxides are acidic in nature.
$B$. $\mathrm{TeO}_2$ is an oxidising agent while $\mathrm{SO}_2$ is reducing in nature.
$C$. The reducing property decreases from $\mathrm{H}_2 \mathrm{~S}$ to $\mathrm{H}_2 \mathrm{Te}$ down the group.
$D$. The ozone molecule contains five lone pairs of electrons.
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