Compound (x) in the above reaction is - Vidyadip

MCQ

Compound $(x)$ in the above reaction is

A
$\begin{matrix}
O\, \\
||\,\, \\
Ph-C-C{{H}_{3}} \\
\end{matrix}$
✓
$\begin{matrix}
\,\,\,O \\
\,\,\,|| \\
Ph-C-H \\
\end{matrix}$
C
$\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
Ph-C{{H}_{2}}-C-H \\
\end{matrix}$
D
$\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
Ph-C{{H}_{2}}-C-C{{H}_{3}} \\
\end{matrix}$

✓

Answer

Correct option: B.

$\begin{matrix}
\,\,\,O \\
\,\,\,|| \\
Ph-C-H \\
\end{matrix}$

b
$(b)$ $\begin{matrix}
\,\,\,O \\
\,\,\,|| \\
Ph-C-H \\
\end{matrix}$ Nucleophilic addition take place and then hemiacetal will form which will undergo nucleophilic attack.

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