MCQ
Compounds showing hydrogen bonding among $HF,\,\,N{H_3},\,\,{H_2}S$ and $P{H_3}$ are
- AOnly $HF,\,\,N{H_3}$ and $P{H_3}$
- BAll the four
- COnly $N{H_3},\,\,{H_2}S$ and $P{H_3}$
- ✓Only $HF$ and $N{H_3}$
✓
Answer
Correct option: D.
Only $HF$ and $N{H_3}$
d
$HF$ has the hydrogen bond. The electronegativity difference is the large and therefore has the permanent dipole. $NH _3$ also form hydrogen bonds .
$HF$ has the hydrogen bond. The electronegativity difference is the large and therefore has the permanent dipole. $NH _3$ also form hydrogen bonds .
Hydrogen bond is formed between two molecules if they have hydrogen and any of the three electronegative atoms $(N,O,F)$ covalently bonded to each other . As there is no $( N , O , F )$ in $H _2 S$ and $PH _3$, there is no hydrogen bond there although it has dipole dipole forces.
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