Question
Compute the derivative of $f(x) = \sin^2 x.$

Answer

We have,
$f(x) = \sin^2x$
$\therefore \quad \frac { d f ( x ) } { d x } = \frac { d } { d x } ( \sin x \sin x )$
$= (\sin x) \frac { d } { d x } \sin x + \sin x \frac { d } { d x } (\sin x) [$using Leibnitz rule$]$
$= (\cos x) \sin x + \sin x(\cos x)$
$= 2 \sin x \cos x = \sin 2x$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free