Question
Compute the following:
$\begin{bmatrix}\text{a} & \text{b} \\-\text{b} & \text{a} \end{bmatrix}+\begin{bmatrix}\text{a} & \text{b} \\\text{b} & \text{a} \end{bmatrix}$

Answer

$\begin{bmatrix}\text{a} &\text{b}\\ \text{-b}&\text{a}\end{bmatrix}+\begin{bmatrix}\text{a} &\text{b}\\ \text{b}&\text{a}\end{bmatrix}=\begin{bmatrix}\text{a+a}& \text{b+b}\\ \text{-b+b}& \text{a+a}\end{bmatrix}=\begin{bmatrix}2\text{a}&2\text{b}\\0& 2\text{a}\end{bmatrix}$

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