Question
Compute the value of x in the following figures.
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Answer
$\angle\text{ABC}=180^\circ-120^\circ=60^\circ$ [Linear pair]$\angle\text{ACB}=180^\circ-110^\circ=70^\circ$ [Linear pair]
$\therefore\text{e}\angle\text{BAC}=\text{x}$
$=180^\circ-\angle\text{ABC}-\angle\text{ACB}=180^\circ-60^\circ-70^\circ=50^\circ$ [Sum of all angles of a triangle]
$\therefore\text{e}\angle\text{BAC}=\text{x}$
$=180^\circ-\angle\text{ABC}-\angle\text{ACB}=180^\circ-60^\circ-70^\circ=50^\circ$ [Sum of all angles of a triangle]
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