Question
Compute the value of x in the following figures.
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Answer
$\angle\text{BAC}=180^\circ-120^\circ=60^\circ$ [Linear pair]$\angle\text{ACB}=180^\circ-112^\circ=68^\circ$ [Linear pair]
$\therefore\text{x}=180^\circ-\angle\text{BAC}-\angle\text{ACB}$
$=180^\circ-60^\circ-68^\circ=52^\circ$ [Sum of all angles of a triangle]
$\therefore\text{x}=180^\circ-\angle\text{BAC}-\angle\text{ACB}$
$=180^\circ-60^\circ-68^\circ=52^\circ$ [Sum of all angles of a triangle]
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