Maharashtra BoardEnglish MediumSTD 9MathsTriangle And lts Angles2 Marks
Question
Compute the value of x in the following figures.
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Answer
$\angle\text{BAE}=\angle\text{EDC}=52^\circ$ [Alternate angles]$\therefore\angle\text{DEC}=\text{x}=180^\circ-40^\circ-\angle\text{EDC}$
$=180^\circ-40^\circ-52^\circ$
$=180^\circ-92^\circ=88^\circ$ [Sum of all angles of a triangle]
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