MCQ
Conc. ${H_2}S{O_4}$ reacts with ${C_2}{H_5}OH$ at ${170\,^o}C$ to form
- A$C{H_3}COC{H_3}$
- B$C{H_3}COOH$
- C$C{H_3}CHO$
- ✓${C_2}{H_4}$
✓
Answer
Correct option: D.
${C_2}{H_4}$
d
(d)$\underset{\text{Ethanol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\underset{{{170}\,^{o}}C}{\mathop{\xrightarrow{Conc.\,{{H}_{2}}S{{O}_{4}}}}}\,\underset{\text{Ethane}}{\mathop{{{C}_{2}}{{H}_{4}}}}\,+{{H}_{2}}O$
(d)$\underset{\text{Ethanol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\underset{{{170}\,^{o}}C}{\mathop{\xrightarrow{Conc.\,{{H}_{2}}S{{O}_{4}}}}}\,\underset{\text{Ethane}}{\mathop{{{C}_{2}}{{H}_{4}}}}\,+{{H}_{2}}O$
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