MCQ
Concentrated nitric acid reacts with iodine to give:
- A$HOI$
- B$HI$
- ✓$HOIO_2$
- D$HOClO_3$
✓
Answer
Correct option: C.
$HOIO_2$
c
${I_2} + 10HN{O_3} \to 2HI{O_3} + 10N{O_2} + 4{H_2}O$
${I_2} + 10HN{O_3} \to 2HI{O_3} + 10N{O_2} + 4{H_2}O$
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$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}$ $\xrightarrow{{{I}_{2}}/NaOH}\underset{\begin{smallmatrix}
yellow\,\,compound \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+
\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(B)
\end{smallmatrix}}{\mathop{(A)}}\,$ $\xrightarrow[\Delta ]{{Ag - powder}}(C)$ $\xrightarrow{{Dil\,\,{H_2}S{O_4}/HgS{O_4}}}(D)$
→O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}$ $\xrightarrow{{{I}_{2}}/NaOH}\underset{\begin{smallmatrix}
yellow\,\,compound \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+
\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(B)
\end{smallmatrix}}{\mathop{(A)}}\,$ $\xrightarrow[\Delta ]{{Ag - powder}}(C)$ $\xrightarrow{{Dil\,\,{H_2}S{O_4}/HgS{O_4}}}(D)$
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