MCQ
Concentration $C{N^ - }$ in $0.1\,M\,HCN$ is $[{K_a} = 4 \times {10^{ - 10}}]$
- A$2.5 \times {10^{ - 6}}M$
- B$4.5 \times {10^{ - 6}}M$
- ✓$6.3 \times {10^{ - 6}}M$
- D$9.2 \times {10^{ - 6}}M$
✓
Answer
Correct option: C.
$6.3 \times {10^{ - 6}}M$
c
Concentration of $CN ^{-1} \sqrt{ K _{ a } \cdot C }$
Concentration of $CN ^{-1} \sqrt{ K _{ a } \cdot C }$
$=\sqrt{4 \times 10^{-10} \times 0.1}$
$=6.3 \times 10^{-6} \,M$
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