MCQ
Conductivity k, is equal to ____________.
- A$\frac{1}{\text{R}}\frac{1}{\text{A}}$
- B$\frac{\text{G}^*}{\text{R}}$
- C$\wedge_{\text{m}}$
- D$\frac{\text{l}}{\text{A}}$
✓
Answer
-
$\frac{1}{\text{R}}\frac{1}{\text{A}}$
-
$\frac{\text{G}^*}{\text{R}}$
Explanation:
$\text{R}=\frac{\rho\text{L}}{\frac{\text{Al}}{\rho}}=\frac{1}{\text{R}}\frac{1}{\text{A}}$
Conductivity k = Conductance (G) × Cell constant (G*)
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