Question
Consider a Young’s double slit experiment as shown in figure. What should be the slit separation $d$ in terms of wavelength $\lambda $ such that the first minima occurs directly in front of the slit $(S_1)$?
✓
Answer
$\sqrt{(2 d)^{2}+(d)^{2}}-2 d=\frac{\lambda}{2}$
$\Rightarrow \quad(\sqrt{5}-2) d=\frac{\lambda}{2}$
$\Rightarrow \quad d=\frac{\lambda}{2(\sqrt{5}-2)}$
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