MCQ
Consider an arithmetic series and a geometric series having four initial terms from the set $\{11,8,21,16,26,32,4\}$ If the last terms of these series are the maximum possible four digit numbers, then the number of common terms in these two series is equal to .......
  • $3$
  • B
    $1$
  • C
    $2$
  • D
    $4$

Answer

Correct option: A.
$3$
a
$G P : 4,8,16,32,64,128,256,512,1024,2048,4096,8192$

$A P : 11,16,21,26,31,36$

Common terms : $16,256,4096$ only

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