MCQ
Consider the above reaction, the compound $'A'$ is
- A
- B
- ✓
- D
✓
Answer
Correct option: C.
c
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Similar questions
Match List $I$ with List $II$ :
→|
LIST $I$ (Compound) |
LIST $II$ (Uses) |
| $A$ Iodoform | $I$ Fire extinguisher |
| $B$ Carbon tetrachloride | $II$ Insecticide |
| $C$ $CFC$ | $III$ Antiseptic |
| $D$ $DDT$ | $IV$ Refrigerants |
Choose the correct answer from the options given below :
$\text{Phenol }\underset{\text{Distillation}}{\mathop{\xrightarrow{Zn}}}\,A\underset{\text{Conc}\text{. }HN{{O}_{3}}}{\mathop{\xrightarrow{\text{Conc}\text{. }{{H}_{2}}S{{O}_{4}}}}}\,B\underset{NaOH}{\mathop{\xrightarrow{Zn}}}\,C$
→In the above reaction $A, B$ and $C $ are the following compounds
How many structural isomers are possible with the molecular formula $C _4 H _{10} O$ :
→Which of the following electronic configuration would be associated with the highest magnetic moment?
Compound $A$ gives $D-$Galactose and $D-$Glucose on hydrolysis. The compound $A$ is:
→For the reduction of $\mathrm{NO}_3^{-}$ion in an aqueous solution, $\mathrm{E}^0$ is $+0.96 \mathrm{~V}$. Values of $\mathrm{E}^0$ for some metal ions are given below
→$\mathrm{V}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{V} \ \ \ \ \mathrm{E}^0=-1.19 \mathrm{~V} $
$\mathrm{Fe}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \ \ \ \ \mathrm{E}^0=-0.04 \mathrm{~V} $
$\mathrm{Au}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Au} \ \ \ \ \mathrm{E}^0=+1.40 \mathrm{~V} $
$\mathrm{Hg}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg} \ \ \ \ \mathrm{E}^0=+0.86 \mathrm{~V}$
The pair$(s)$ of metals that is$(are)$ oxidized by $\mathrm{NO}_3^{-}$in aqueous solution is$(are)$
$(A)$ $\mathrm{V}$ and $\mathrm{Hg}$ $(B)$ $\mathrm{Hg}$ and $\mathrm{Fe}$
$(C)$ $\mathrm{Fe}$ and $\mathrm{Au}$ $(D)$ $Fe$ and $V$
The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is
$C{H_3} - C{H_2} - C{H_2}Br + KOH{\rm{ (alc}}{\rm{.)}} \to {\rm{Product}}$
→Product in above reaction is
The product of $I^-$ with $MnO_4^-$ in alkaline medium is
→Phenol is obtained by heating aqueous solution of