MCQ
Consider the above reaction, the major product $"P"$ formed is:
- A
- B
- ✓
- D
✓
Answer
Correct option: C.
c
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A solution made up of numerous components in which each component’s property is the weighted sum of its separate properties. The answer is:
$N{H_3}{\mkern 1mu} {\mkern 1mu} + {\mkern 1mu} {\mkern 1mu} {O_2}{\mkern 1mu} \xrightarrow[{500K\,}]{{Pt}}{\mkern 1mu} A{\mkern 1mu} + {\mkern 1mu} {H_2}O$
→$A\, + \,{O_2}\, \to \,B\,\,\,;\,\,\,B\, + \,{H_2}O\, \to \,C\, + \,A$
$A\,\,B$ and $C$ respectively are
Reason of lanthanoid contraction is
A $0.2$ molal aqueous solution of a weak acid $(HX) $ is $20$ percent ionised. The freezing point of this solution is .......... $^oC$. ($K_f = 1.86\,K/m$ for water) :-
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→Reason : $H^+$ ion given by carboxylic group $(-COOH)$ is captured by amino group $(-NH_2)$ having lone pair of electrons.
The vapour pressure of water at $20\,^oC$ is $17.54\,mm$. When $20\,g$ of a non-ionic, substance is dissolved in $100\,g$ of water, the vapour pressure is lowered by $0.30\,mm$ . What is the molecular weight of the substances
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Value of Henry’s constant KH __________.
In the following sequence, products $\mathrm{I}, \mathrm{J}$ and $\mathrm{L}$ are formed. $\mathrm{K}$ represents a reagent.
→$Image$
$1.$ The structure of the product $\mathrm{I}$ is
A,B,C,D, $Image$
$2.$ The structures of compounds $J$ and $K$ respectively are
A,B,C,D, $Image$
$3.$ The structure of product $L$ is
A,B,C,D, $Image$
Give the answer question $1,2$ and $3.$
Use the data given in and find out the most stable ion in its reduced form.
$\text{E}^\ominus_{\text{cr}_2\text{O}^{2-}_7/\text{cr}^{3+}}=1.33\text{V}\ \ \ \text{E}^\ominus_{\text{Cl}_2/\text{Cl}^-}=1.36\text{V}$
$\text{E}^\ominus_{\text{MnO}^-_4/\text{Mn}^{2+}}=1.51\text{V}\ \ \ \ \text{E}^\ominus_{\text{Cr}^{3+}/\text{Cr}}=-0.74\text{V}$
→$\text{E}^\ominus_{\text{cr}_2\text{O}^{2-}_7/\text{cr}^{3+}}=1.33\text{V}\ \ \ \text{E}^\ominus_{\text{Cl}_2/\text{Cl}^-}=1.36\text{V}$
$\text{E}^\ominus_{\text{MnO}^-_4/\text{Mn}^{2+}}=1.51\text{V}\ \ \ \ \text{E}^\ominus_{\text{Cr}^{3+}/\text{Cr}}=-0.74\text{V}$