$Ag\left( s \right)/A{g^ \oplus }||C{u^{2 + }}/Cu\left( s \right)$
$A{g^ \oplus } + {e^ - } \to Ag\,;\,{E^o} = x$
$C{u^{2 + }} + 2{e^ - } \to Cu\,;\,{E^o} = y$
$E^o_{cell}$ is
$E_{\text {Cell }}^{0}=\mathrm{y}-\mathrm{x}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Experiment No. | $\begin{array}{c}{[ A ]} \\ \left( mol dm ^{-3}\right)\end{array}$ | $\begin{array}{c}{[ B ]} \\ \left( mol dm ^{-3}\right)\end{array}$ | $\begin{array}{c}{[ C]} \\ \left( mol dm ^{-3}\right)\end{array}$ | Rate of reaction $\left( mol dm ^{-3} s ^{-1}\right)$ |
| $1$ | $0.2$ | $0.1$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $2$ | $0.2$ | $0.2$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $3$ | $0.2$ | $0.1$ | $0.2$ | $1.2 \times 10^{-4}$ |
| $4$ | $0.3$ | $0.1$ | $0.1$ | $9.0 \times 10^{-5}$ |
The rate of the reaction for $[ A ]=0.15 mol dm ^{-3},[ B ]=0.25 mol dm ^{-3}$ and $[ C ]=0.15 mol dm ^{-3}$ is found to be $Y \times 10^{-5} mol dm d ^{-3} s ^{-1}$. The value of $Y$ i. . . . . . .
$(1)\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
| \\
{{C_2}{H_5}C{H_2}C - OC{H_3}} \\
| \\
{\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(2)\,\,\begin{array}{*{20}{c}}
{{C_2}{H_5}C{H_2}C = C{H_2}} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(3)\,\,\begin{array}{*{20}{c}}
{{C_2}{H_5}CH = C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$