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STD 12 - 2. Electrochemistry — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 2. Electrochemistry4 Marks
MCQ
Consider the cell whose $emf$ is $1.01\, V$.

$\mathop {{H_2}(Pt)}\limits_{1\,atm} \left| {\begin{array}{*{20}{c}}
{H_{aq}^ + }\\
{pH = 4}
\end{array}} \right|\left| {\begin{array}{*{20}{c}}
{A{g^ + }}\\
{xM}
\end{array}} \right|\begin{array}{*{20}{c}}
{Ag}\\
{}
\end{array}$

What is the value of $x$ ? ........... $\mathrm{M}$

( give : $E_{A{g^ + }|Ag}^o = + 0.8$   $\frac{{2.303\,RT}}{F} = 0.06 $)

  • A
    $0.05$
  • B
    $0.69$
  • C
    $0.15$
  • ✓
    $0.31$
✓

Answer

Correct option: D.
$0.31$
d
$\mathrm{H}_{2}+2 \mathrm{Ag}^{+} \longrightarrow 2 \mathrm{H}^{+}+2 \mathrm{Ag}$

$E=E^{\circ}-\frac{0.06}{2} \log \frac{\left(10^{-4}\right)^{2}}{1 \times x^{2}}$

$1.01=0.8-0.03 \log \frac{10^{-8}}{x^{2}}$

$0.21=-0.03 \log \frac{10^{-8}}{x^{2}}$

$-7=\log \frac{10^{-8}}{x^{2}}$

$10^{-7}=\frac{10^{-8}}{x^{2}}$

$x=\frac{1}{\sqrt{10}}=0.316 \,\mathrm{M}$

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