Question
Consider the compounds, $BCl_3$ and $CCl_4$. How will they behave with water? Justify.
✓
Answer
$BCl_3$ is an electron deficient compound. Also, it has an empty unhybridised p-orbital which can accept electrons. In presence of water, $BCl_3$ hydrolyses and forms $B(OH)_3$.
But, when $CCl_4$ is mixed with water, no reaction takes place because carbon neither has any unhybridised, empty p-orbital where it can accommodate electrons from water nor it has empty d-orbital.
$CCl_4 + H_2O$ → No reaction.
But, when $CCl_4$ is mixed with water, no reaction takes place because carbon neither has any unhybridised, empty p-orbital where it can accommodate electrons from water nor it has empty d-orbital.
$CCl_4 + H_2O$ → No reaction.
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