The correct order of their acidity is 
- ✓$II > I > III > IV$
- B$II > III > I > IV$
- C$IV > III > IV > I$
- DNone of these
The correct order of their acidity is 

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$MnCl _2+ K _2 S _2 O _8+ H _2 O \longrightarrow KMnO _4+ H _2 SO _4+ HCl$ (equation not balanced).
Few drops of concentrated $HCl$ were added to this solution and gently warmed. Further, oxalic acid ( $225 mg$ ) was added in portions till the colour of the permanganate ion disappeared. The quantity of $MnCl _2$ (in $mg$ ) present in the initial solution is. . . . . . . . . (Atomic weights in $g mol ^{-1}: Mn =55, Cl =35.5$ )
$(A)$ $\Lambda \stackrel{0}{ m }$ for electrolyte $A$ is obtained by extrapolation
$(B)$ For electrolyte B, vx $\Lambda m$ vs $\sqrt{ c }$ graph is a straight line with intercept equal to $\Lambda \stackrel{0}{ m }$
$(C)$ At infinite dilution, the value of degree of dissociation approach zero for electrolyte $B$.
$(D)$ $\Lambda \stackrel{0}{ m }$ for any electrolyte $A$ or $B$ can be calculated using $\lambda^{\circ}$ for individual ions.