MCQ
Consider the following

$\begin{array}{l}
C{H_3} - C{H_2} - N{H_2}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(I)}}
\end{array}$

$\begin{array}{l}
Ph - C{H_2} - N{H_2}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(II)}}
\end{array}$ 

 $\begin{array}{l}
Ph - N{H_2}\\
\,\,\,\,\,\,\,\,\,{\rm{(III)}}
\end{array}$

Correct order of their basic strength is

  • A
    $III > II > I$
  • $I > II > III$
  • C
    $I > III > II$
  • D
    $II > I > III$

Answer

Correct option: B.
$I > II > III$
b
Order of basic strength is

$\underbrace{C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}}_{+\,I}$ $>\underbrace{Ph}_{-\,I}-C{{H}_{2}}-N{{H}_{2}}$ $>\,\underset{\begin{smallmatrix} 
 delocalise \\ 
 l.p. 
\end{smallmatrix}}{\mathop{Ph\,-\,\underset{\scriptscriptstyle\centerdot\centerdot}{N}{{H}_{2}}}}\,$

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