$M(s) \to M(g)\,\,\,\,\,\,\,\,\,\,\,\,\,\, ........(1)$
$M(s) \to M^{2+} (g) + 2e^-\,\,\,\,\,\,\,\,.......(2)$
$M(g) \to M^+(g) + e^-\,\,\,\,\,\,\,\,\,\,\,.........(3)$
$M^+ (g) \to M^{2+} (g) + e^-\,\,\,\,\,\,\,\,\,.........(4)$
$M(g) \to M^{2+} (g) +2e^-\,\,\,\,\,\,\,\,\,\,\,..........(5)$
The second ionization energy of $M$ could be calculated from the energy values assoclated with
Hence, $M(g) \to M^{2+} + 2e^-$ $........(5)$
$M(g) \to M^+ + e^-$ $.........(3)$
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Which combination gives the highest yield of $z,$ at equilibrium.
$(A)$ The $pH$ of $1 \times 10^{-8}\,M\,HCl$ solution is $8$.
$(B)$ The conjugate base $H _2 PO _4^{-}$is $HPO _4{ }^{2-}$.
$(C)$ $K _{ w }$ increases with increase in temperature.
$(D)$ When a solution of weak monoprotic acid is titrated against a strong base at half neutralisation point, $pH =\frac{1}{2} pK _{ a }$
Choose the correct answer from the option given below.