$Co = 6$;
$O. N. = x + 5 \times (0) + 1 \times (-2) + 1\times (-1) = 0$
$\therefore $ $x = + 3$ ; electronic configuration of
$Co^{3+}[Ar]\, 3d^64s^0$ hence number of $d$ electrons is $6$. All $d-$ electrons are paired due to strong ligand hence unpaired electron is zero.
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| Column $-I$ | Column $-II$ | ||
| $(a)$ | $[Pt(NH_3)_3Cl]Br$ | $(P)$ | Coordination isomerism |
| $(b)$ | $[Cr(NH_3)_5(NCS)]^{+2}$ | $(Q)$ | Ionisation isomerism |
| $(c)$ | $[Co(H_2O)_6]Cl_3$ | $(R)$ | Linkase isomerism |
| $(d)$ | $[PtCl_4] [Pt(NH_3)_4]$ | $(S)$ | Hydrated isomerism |
$(A)$ Albumin is a simple protein
$(B)$ The amino acid alanine contains an acidic side chain
$(C)$ Insulin is a hormone
$(D)$ Muscles contain the protein keratin
Point out the wrong statements in the above set of statements
$(1)$ In gas phase $SO_2$ molecule is $V-$ shape.
$(2)$ In gas Phase $SO_3$ molecule is planar
$(3)$ $\gamma - SO_3$ is cyclic trimer
Which oi the above statement are correct ?