Download App

5. Co-ordination chemistry — Chemistry STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceChemistry5. Co-ordination chemistry1 Mark
MCQ
Consider the following complexes.

$\left[\mathrm{CoCl}\left(\mathrm{NH}_3\right)_5\right]^{2+}, \quad\left[\mathrm{Co}(\mathrm{CN})_6\right]^{3-} \text {, }$

$(A)$                                        $(B)$

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{H}_2 \mathrm{O}\right)\right]^{3+}, \quad\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{2+}$

$(C)$                                       $(D)$

The correct order of $A$, $B$, $C$ and $D$ in terms of wavenumber of light absorbed is :

  • A
    $C $<$ D $<$ A $<$ B$
  • ✓
    $D $<$ A $<$ C $<$ B$
  • C
    $A $<$ C $<$ B $<$ D$
  • D
    $B $<$ C $<$ A $<$ D$
✓

Answer

Correct option: B.
$D $<$ A $<$ C $<$ B$
b
As ligand field increases, light of more energy is absorbed

Energy $\propto$ wave number

$(\bar{v})$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5. Co-ordination chemistry→5. Co-ordination chemistry — all question types→Chemistry STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on hydrolysis forms a racemic mixture of $\alpha -$hydroxy acid. The carbonyl compound is
→
The oxidation number of chromium in sodium tetrafluoro oxochromate complex is
→
The structure of the starting compound $P$ used in the reaction given below is :
→
Empty space in $\text{ccp}$ lattice is:
→
Ethanol can be prepared more easily by which reaction ?
$(i)\, CH_3CH_2Br + H_2O \longrightarrow CH_3CH_2OH$
$(ii)\, CH_3CH_2Br + Ag_2O\, (in\, boiling\, water) \longrightarrow CH_3CH_2OH$
→
Silver sulphide dissolved in a solution of sodium cynamide to form the complex
→
Reaction of    $R-C -NH_2$ with a mixture of $Br_2$ and $KOH$ gives 
                              $||$
                              $O$
 $R -NH_2$ asthe  main product. The intermediates involved in this reaction are :-

$(A)$ $\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,  \\
   R-C-NHBr  \\
\end{matrix}$               $(B)$ $R-NH-Br$

$(C)$ $R-N=C=O$                $(D)$ $\begin{matrix}
   \,\,\,\,O\,\,\,\,\,\,\,\,\,\,  \\
   \,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,  \\
   R-C-NB{{r}_{2}}  \\
\end{matrix}$

→
What fraction of chlorine will be precipitated as $AgCl$ by using $AgNO_3$ from $[CrCl(NH_3)_5]Cl_2$
→
Glycerol was distilled with oxalic acid crystals and the products were led into Fehling solution and warmed. Cuprous oxide was precipitated. It is due to
→
The reaction of $Xe$ and $O _2 F _2$ gives a $Xe$ compound $P$. The number of moles of $HF$ produced by the complete hydrolysis of $1 mol$ of $P$ is. . . . . .
→