MCQ
Consider the following $E_1 /S_{N^1}$ reaction
The missing product $(s)$ is $(are)$
- ✓$1, 2$ and $3$
- B$3$ and $4$
- C$2$ and $3$
- D$1, 2, 3$ and $4$
The missing product $(s)$ is $(are)$

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$A$. $\mathrm{Fe}$ $B$. $\mathrm{Mn}$ $C$. $\mathrm{Ni}$ $D$. $\mathrm{Cr}$ $E$. $\mathrm{Cd}$
Choose the correct answer from the options given below:
(image) $\xrightarrow{{[O]}}A\xrightarrow{{SOC{l_2}}}B\xrightarrow{{Na{N_3}}}C\xrightarrow{{Heat}}D$
The two products formed in above reaction are -