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Consider the following reaction : Here $, A, B, C$ and $D$ respectively are :

• A
  $\text{A} = \text{Conc. HCl; B} = \text{Fe; C} = \text{NH}_4\text{OH; D}= \text{PbO}$
• B
  $\text{A} = \text{Conc. H}_2\text{SO4; B} = \text{Fe; C} = \text{NH}_4\text{OH; D} = \text{Pb(NO}_3)2$
• ✓
  $\text{A} = \text{Conc. H}_2\text{SO}_4\text{; B} = \text{Fe; C} = \text{NH}_3\text{; D}= \text{Pb(NO}_3)2$
• D
  $\text{A} = \text{Conc. HCl; B} = \text{Fe; C} = \text{NH}_3\text{; D} =\text{PbO}$